0024陽気な名無しさん2022/03/09(水) 17:27:47.180 p[0]=1 p[1]=1/3 p[n+1]=2/3-p[n]/3 p[n]=(1/2){(-1/3)^n+1} a[n]={p[n]-(1/3)^n}/2+(1/3)^n =(1/4){(-1/3)^n+1}+(1/2)(1/3)^n =(1/4){1+(2+(-1)^n)/3^n} a[1]=1/3 a[2]=1/3 a[3]=7/27 a[4]=7/27 a[5]=61/243 a[6]=61/243